鄯善Design and calculation of industrial coolers

dustrial coolers,design

：本文围绕工业冷却器的设计与计算展开，阐述了工业冷却器在工业生产中的关键作用，其能有效地降低设备或工艺流程的温度，保障系统稳定运行，详细介绍了设计环节，包括依据不同的工业场景和冷却需求确定冷却器的类型，如风冷式、水冷式等，同时考虑冷却介质的特性、流量等参数，在计算方面，着重讲解了热负荷的计算方法，通过分析被冷却对象的热量产生速率、环境温度等因素，精准计算出所需的换热量，还涉及冷却器传热面积、传热系数等关键参数的计算，以确保冷却器能达到预期的冷却效果。

鄯善1、Design basis

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鄯善Design Standard for Steel Structures GB50017-2017Steel Structure Design Manual, China Construction Industry Press, January 2004

鄯善Code for Construction and Acceptance of Steel Structures (GB50205-2020)

鄯善British Code for Design of Steel Structures (BS5950)

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2、Design load

鄯善Load includes structural self weight, wind turbine constant load, live load, snow load, wind load, etc. The structural calculation adopts the ultimate stress method, therefore, the load value is larger than usual. The surface load is calculated based on the distribution coefficient and applied to the platform according to the line load. The wind load is calculated based on the wind vibration coefficient, body shape coefficient, and basic wind pressure to calculate the wind pressure values on four surfaces, which are then converted into line loads and applied to the columns. Auxiliary components such as stair handrails are applied to the stairs according to uniformly distributed loads.

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1. Constant load

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鄯善The self weight of the steel structure is automatically calculated by the program, and the node weight is considered based on the self weight of the structure multiplied by 1.3. The weight and fluid load of the radiator are applied by external forces.

鄯善Platform constant load: 0.50kN/m2

2. Live load

鄯善Live load of the platform for loading: 2.5kN/m2

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鄯善3. Snow load

According to relevant design data, the snow pressure can be basically calculated as 0.4N/m2.

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鄯善4. Wind load

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Calculate according to the maximum value.

鄯善Basic wind pressure: 0.35kN/m2, height variation coefficient of 1.8, wind vibration coefficient: 1.5, ground roughness category: Class A

Class.

Is the standard value of wind load, is the wind vibration coefficient at height Z, is the shape coefficient of wind load, and is the coefficient of wind pressure height variation.

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When the standard value of wind load is less than 0.75kpa, calculate based on 0.75 kPa and multiply by 1.4 times the safety factor. Namely

5. Temperature load

鄯善The temperature difference is relatively small. The structural form is single, and the linear expansion of steel has a relatively small impact on the overall performance of the structure, which can be ignored.

鄯善6 Earthquake loads

According to the seismic analysis design method: small earthquakes do not damage, medium earthquakes are repairable, and large earthquakes do not collapse. Small earthquake analysis can be divided into: bottom shear force method, response spectrum analysis, and elastic time history analysis. Medium earthquake analysis is calculated by multiplying small earthquake analysis by amplification factor.

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鄯善Seismic fortification intensity: 8 degrees

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Design basic seismic acceleration peak value: 0.3g

鄯善Construction site category: II site

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Design grouping: Second group

鄯善Damping ratio: 0.05

鄯善This structure adopts MIADS software for overall modeling and analysis. During modeling, beam elements are mainly used for each structure. In order to facilitate loading, plate elements are established at the structural platform. Consolidation is used as the boundary condition at the bottom of each column, and constraints are applied at the connection between the column and the original structure according to the actual situation. The structure includes upright column, cross brace, slant support and upper and lower platform steel structure.

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鄯善Load sub factors and load combinations:

鄯善Number	load	鄯善Partial    coefficient remarks	Partial    coefficient remarks 鄯善
1 鄯善	鄯善dead load 鄯善	鄯善1.3 鄯善
鄯善2 鄯善	Dead load, when   it has a restraining effect on uplift and   overturning 鄯善	鄯善1.0
3	Dead load, when   acting together with wind load and live load 鄯善	1.2
4 鄯善	鄯善Live load 鄯善	1.6
5	鄯善Live load, when   combined with wind load	1.2
6	鄯善Wind load 鄯善	1.4 鄯善
7 鄯善	When combined   with wind load and live load	1.2

鄯善3、 Radiator calculation

鄯善1. Material parameters

Aluminum alloy adopts 6005-T1, with tensile strength and yield strength equivalent to 6063-T5, tensile strength ≥ 150Mpa, yield stress ≥ 110 Mpa. According to the performance table of aluminum alloy, it is found that 6063-T5 has a tensile strength of 185Mpa, yield stress of 145 Mpa, and fatigue strength of 90MPa.

鄯善2. Working condition analysis

鄯善The calculation of radiators can be divided into 1. lifting ondition,

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鄯善3. operating condition (operating condition is divided into

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4.support and lifting point participate in force simultaneously.

鄯善5.support bears gravity, while lifting point bears horizontal force.

6.support does not bear any force, that is, when the overall structure is subjected to uneven settlement, there is a suspension at the bottom)

To ensure its stability, it is recommended that the foundation treatment should be pre compressed and settlement assessment should be carried out during the overall installation.

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鄯善2.1 Hoisting conditions

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鄯善At this point, the radiator is only considered for its own weight due to the lack of fluid injection, and is lifted and installed through a side lifting point. Because no other accessories were installed during modeling, in order to estimate the weight more accurately, its self weight coefficient was defined as 1.3.

鄯善The radiator structure consists of 1, frame 2, support beam 3, heat exchange tube 4, tube plate, and other ancillary structures. As the heat exchange tube and support beam are fixed together through a corrugated plate, it can be considered that the heat exchange tube participates in the structural stress, which leads to strain and stress generation.

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鄯善The overall structural model is

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Radiator structural model

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The overall deformation of the radiator during the lifting process

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Stress cloud diagram of radiator during lifting process

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鄯善From its displacement cloud map, it can be seen that its overall deformation is 1.2mm, and the maximum stress is 15MPa

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Stress cloud map of heat sink

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鄯善Displacement cloud map of heat sink

鄯善From its displacement cloud map, it can be seen that its overall deformation is 1mm and the maximum stress is 2MPa. Through calculation, it can be seen that horizontal lifting has little effect on the heat dissipation fins, and its deformation and stress are far less than the standard requirements.

鄯善The vertical lifting situation is as follows:

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鄯善Vertical lifting stress cloud map

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